A) \[\frac{11}{2}\]
B) \[\frac{11}{4}\]
C) 3
D) \[\frac{1}{4}\]
Correct Answer: B
Solution :
\[{{C}_{6}}{{H}_{12}}\left( g \right)={{p}_{1}}\] \[={{p}_{2}}-3{{p}_{1}}+{{p}_{1}}=30mm\] \[{{p}_{2}}-2{{p}_{1}}=30mm\] Hence, \[{{\text{p}}_{\text{1}}}\text{=10mm, }{{\text{p}}_{\text{2}}}\text{=50mm}\]
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