A) (-2, 5, -1)
B) (4, 5, 1)
C) (2, -5, 1)
D) (4, 5, -1)
Correct Answer: D
Solution :
Given equation of sphere is \[Q=ms\Delta \theta =0.1\times 250\times 0.4\] Centre \[2C\times {{10}^{4}}=10\] If one of the end of diameter is (2, 7, 3). Let the other end of the diameter be (x, y, z). \[\Rightarrow \] \[C=\frac{10}{2\times {{10}^{4}}}=5\times {{10}^{-4}}\] \[\therefore \] 2 + x = 6 \[C=500\mu F\] x = 4 7 + y = 12 \[{{C}_{0}}=\frac{{{\varepsilon }_{0}}A}{d}=3\mu F\] y = 5 and 3 + z = 2 \[{{\varepsilon }_{r}}\] z = - 1 Therefore, (x, y, z) \[C=\frac{K{{\varepsilon }_{0}}A}{d}=15\mu F\] (4, 5, - 1)
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