A) \[\left[ \begin{matrix} \text{12} & \text{36} & \text{12} \\ \text{-12} & \text{24} & \text{-36} \\ \text{0} & \text{12} & \text{24} \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} \text{12} & \text{26} & \text{-12} \\ \text{24} & 36 & \text{-36} \\ \text{0} & \text{12} & \text{-24} \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} \text{12} & \text{-12} & 36 \\ \text{24} & -24 & \text{-36} \\ \text{0} & \text{12} & \text{24} \\ \end{matrix} \right]\]
D) None of the above
Correct Answer: A
Solution :
Given \[\begin{align} & Ca{{\left( OH \right)}_{20}}+2C{{O}_{2}}\to Ca{{\left( HC{{O}_{3}} \right)}_{2}} \\ & \text{YExcessZ} \\ \end{align}\] \[\begin{align} & Ca{{\left( HC{{O}_{3}} \right)}_{2}}\xrightarrow{Heat}CaC{{O}_{3}}+C{{O}_{2}}\uparrow +{{H}_{2}}O \\ & ZX \\ \end{align}\] \[\begin{align} & Zn{{\left( OH \right)}_{2}}+2\overset{-}{\mathop{OH}}\,\to ZnO_{2}^{2-}+2{{H}_{2}}O \\ & \text{AcidBaseSaltWater} \\ \end{align}\] \[\begin{align} & Zn{{\left( OH \right)}_{2}}+2{{H}^{+}}\to Z{{n}^{2+}}+2{{H}_{2}}O \\ & \text{BaseAcidSaltWater} \\ \end{align}\] \[{{\left[ \text{Cu}{{\left( \text{N}{{\text{H}}_{\text{3}}} \right)}_{\text{4}}} \right]}^{\text{2+}}}\text{}{{\left[ \text{Cu}{{\left( \text{en} \right)}_{\text{2}}} \right]}^{\text{2+}}}\text{}{{\left[ \text{Cu}\left( \text{trien} \right) \right]}^{\text{2+}}}\text{.}\] \[{{\left[ \text{Fe}{{\left( {{\text{H}}_{\text{2}}}\text{O} \right)}_{\text{6}}} \right]}^{\text{3+}}}\text{}{{\left[ \text{Fe}{{\left( \text{N}{{\text{O}}_{\text{2}}} \right)}_{\text{6}}} \right]}^{\text{3-}}}\text{}{{\left[ \text{Fe}{{\left( \text{N}{{\text{H}}_{\text{3}}} \right)}_{\text{6}}} \right]}^{\text{3-}}}\] \[\because \] \[\text{N}{{\text{O}}_{\text{2}}}^{\text{-}}\] \[{{\text{E}}_{\text{1}}}\text{=}{{\text{E}}_{\text{2}}}\text{=}\frac{\text{1}}{\text{4 }\!\!\pi\!\!\text{ }{{\text{ }\!\!\varepsilon\!\!\text{ }}_{\text{0}}}}\text{.}\frac{\text{q}}{{{\text{r}}^{\text{2}}}}\]
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