A) \[1.2\times {{10}^{14}}Hz\]
B) \[8\times {{10}^{15}}Hz\]
C) \[1.2\times {{10}^{16}}Hz\]
D) \[4\times {{10}^{12}}Hz\]
Correct Answer: B
Solution :
\[\begin{align} & {{H}_{2}}NHgO.HgI+7KI+{{H}_{2}}O \\ & \text{brown ppt}\text{.} \\ & \text{iodineofMillion }\!\!'\!\!\text{ sbase} \\ \end{align}\] \[\begin{align} & HCl+MN{{O}_{3}}\to MCl+HN{{O}_{3}} \\ & \text{Cwhite ppt}\text{.} \\ \end{align}\] As, \[\left( M=A{{g}^{+}},p{{b}^{+}},H{{g}^{+}} \right)\] \[194u=\frac{28.9}{100}\times 194=56u\] \[\therefore \] or, \[\therefore \] or, \[56u=\frac{56}{14}Natom=4Natom\] \[\begin{align} & CaC{{O}_{3}}\xrightarrow{Heat}CaO+C{{O}_{2}}\uparrow \\ & \text{XColourless} \\ & \text{gas} \\ \end{align}\] \[\begin{align} & CaO+{{H}_{2}}O\to Ca{{\left( OH \right)}_{2}} \\ & \text{ResidueY} \\ \end{align}\]
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