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VIT Engineering VIT Engineering Solved Paper-2015

  • question_answer
    For the given reaction, \[{{H}_{2}}\left( g \right)+C{{l}_{2}}\left( g \right)\to 2{{H}^{+}}\left( aq \right)+2C{{l}^{-}}\left( aq \right);\]                                           \[\Delta {{G}^{\circ }}=-262.4kJ\] The value of free energy of formation\[\left( \Delta {{G}^{\circ }}f \right)\] for the ion \[C{{l}^{-1}}\left( aq \right),\] therefore  will be

    A) \[-131.2kJmo{{l}^{-1}}\]               

    B) \[+131.2kJmo{{l}^{-1}}\]

    C) \[\text{-262}\text{.4kJmo}{{\text{l}}^{\text{-1}}}\]

    D) \[\text{+262}\text{.4kJmo}{{\text{l}}^{\text{-1}}}\]

    Correct Answer: A

    Solution :

    \[=\frac{{{10}^{-3}}\times 5\times {{10}^{3}}}{15\times {{10}^{-6}}\times 330}\]\[=\frac{100000}{99}\approx 1010\]   \[\Rightarrow \] or    \[{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}\left( \text{g} \right)\text{=}{{\text{p}}_{\text{1}}}\]                   \[{{H}_{2}}\left( g \right)={{p}_{2}}mm\] or,           \[\therefore \] or,   \[{{p}_{1}}+{{p}_{2}}=60mm\]


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