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VIT Engineering VIT Engineering Solved Paper-2015

  • question_answer
    When copper is treated with a certain concentration of nitric acid/nitric oxide and nitrogen dioxide are liberated in equal volumes according to the equation, \[_{X}Cu+yHN{{O}_{3}}\to Cu{{\left( N{{O}_{3}} \right)}_{2}}+NO+N{{O}_{2}}+{{H}_{2}}O\]The coefficients o X and y are respectively

    A) 2 and 3                 

    B) 2 and 6

    C) 1 and 3                 

    D) 3 and 8

    Correct Answer: B

    Solution :

    Balanced equation for producing NO and \[L=\frac{nh}{2\pi }=\frac{2h}{2\pi }=\frac{h}{\pi }\] respectively are \[\because \]                                                                        ....(i) \[Cu+4HN{{O}_{3}}\xrightarrow[{}]{{}}Cu{{(N{{O}_{3}})}_{2}}+2N{{O}_{2}}+2{{H}_{2}}O\]                                                                      ...(ii) Here NO and \[\therefore \] are evolved in equal volumes, therefore adding Eqs. (i) and (ii) We get \[\lambda \alpha \frac{1}{p}\]or, \[\Rightarrow \]Thus , coefficients x and y of Cu and \[\frac{\Delta p}{p}=-\frac{\Delta \lambda }{\lambda }\] respectively are 2 and 6.


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