A) Wurtz reaction of \[{{C}_{2}}{{H}_{5}}Br\]
B) Hydrolysis of n-butylmagnesium iodide
C) Reduction of propanol with red phosphorus and HI
D) Decarboxylation of 3-methylbutanoic acid
Correct Answer: D
Solution :
Decarboxylation of 3-methylbutanoic acid gives isobutene i.e., \[{{n}^{2}}=4\] \[\Rightarrow \] On the other hand, Wurtz reaction of \[NaN{{H}_{2}}\] gives -n-butane, hydrolysis of n-butyl magnesium bromide also gives n -butane but reduction of propanol with HI/P gives propane.
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