question_answer

In the cannizzaro reaction given below\[2Ph-CHO\xrightarrow{O{{H}^{-}}}\]\[Ph-C{{H}_{2}}-OH+PhCO_{2}^{-}\]the slowest step is

A) the attack of \[\overline{O}H\] at the carbonyl group         

B)  the transfer of hydride ion to the carbonyl group 

C) the abstraction of a proton from the carboxylic acid

D)  the deprotonation of \[Ph-C{{H}_{2}}OH\]

Correct Answer: B

Solution :

Transfer of hydride ion to the carbonyl group is the slowest or the rate determining step.