A) 2.8
B) 0.0
C) 4.0
D) 2.6
Correct Answer: A
Solution :
According to Mulliken, electronegativity of an atom is average of IE and EA (in eV). \[Y\left( n,\alpha \right)\] If IE and EA are in k cal \[\alpha -\] \[_{Z}{{Y}^{A}}{{+}_{0}}{{n}^{1}}{{\to }_{3}}L{{i}^{7}}{{+}_{2}}H{{e}^{4}}\]
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