A) 10\[\Omega \]
B) 30\[\Omega \]
C) 20\[\Omega \]
D) 40\[\Omega \]
Correct Answer: B
Solution :
The resistance of lamp is given by \[t=n{{T}_{1/2}}=0.74\times 4.47\times {{10}^{8}}\] The current in the lamp will be \[t=3.3\times {{10}^{8}}yr\] As the lamp is operated on 120 V DC, then resistance becomes \[Y\left( n,\alpha \right)\] For proper glow, a resistance R is put in series with the bulb so that \[\alpha -\] \[_{Z}{{Y}^{A}}{{+}_{0}}{{n}^{1}}{{\to }_{3}}L{{i}^{7}}{{+}_{2}}H{{e}^{4}}\] \[\Rightarrow \]
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