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VIT Engineering VIT Engineering Solved Paper-2015

  • question_answer
    Consider the following changes \[M\left( s \right)\to M\left( g \right)\]                         ...(1) \[M\left( g \right)\to {{M}^{2+}}\left( g \right)+2{{e}^{-}}\]           ...(2) \[M\left( g \right)\to {{M}^{+}}\left( g \right)+{{e}^{-}}\]                   ...(3) \[{{M}^{+}}\left( g \right)\to {{M}^{2+}}\left( g \right)+2{{e}^{-}}\]              ...(4) \[M\left( g \right)\to {{M}^{2+}}\left( g \right)+2{{e}^{-}}\]                ...(5) The second ionisation energy of M could be determined from the energy values associated with

    A) 1+2+4                                   

    B) 2+3-4

    C) 1+5-3                                    

    D) 5-3

    Correct Answer: D

    Solution :

    Second iomsation energy is the amount of energy required to take out an electron from the mono positive cation. Thus           \[\Rightarrow \]                     \[{{\delta }_{m}}={{180}^{\circ }}-2A\] On subtracting (3) from (5) we get,]                     \[{{P}_{1}}=2D\]


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