A) \[{{\left[ \text{Cu}{{\left( \text{N}{{\text{H}}_{\text{3}}} \right)}_{\text{4}}} \right]}^{\text{2+}}}\text{}{{\left[ \text{Cu}{{\left( \text{en} \right)}_{\text{2}}} \right]}^{\text{2+}}}\text{}{{\left[ \text{Cu}\left( \text{trien} \right) \right]}^{\text{2+}}}\]
B) \[{{\left[ Fe{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{\text{3+}}}\text{}{{\left[ Fe{{\left( N{{O}_{2}} \right)}_{6}} \right]}^{3-}}\text{}{{\left[ Fe{{\left( N{{H}_{3}} \right)}_{6}} \right]}^{\text{3+}}}\]
C) \[{{\left[ Co{{\left( {{\text{H}}_{2}}\text{O} \right)}_{6}} \right]}^{\text{3+}}}\text{}{{\left[ Rh{{\left( {{H}_{2}}O \right)}_{6}} \right]}^{3+}}\text{}{{\left[ lr{{\left( {{H}_{2}}O \right)}_{6}} \right]}^{\text{3+}}}\]
D) \[{{\left[ Cr{{\left( \text{N}{{\text{H}}_{3}} \right)}_{6}} \right]}^{\text{+}}}\text{}{{\left[ Cr{{\left( N{{H}_{3}} \right)}_{6}} \right]}^{2+}}\text{}{{\left[ Cr{{\left( N{{H}_{3}} \right)}_{6}} \right]}^{\text{3+}}}\]
Correct Answer: B
Solution :
Increasing stability order \[\Rightarrow \]Their formation of entropy increases in the same order due to denticity of ligand increases. \[-35={{m}_{0}}\times 35\]\[\Rightarrow \] \[{{m}_{0}}=-10\] is stronger ligand than \[\text{ }\!\!\mu\!\!\text{ =}\frac{\text{sin}\left( \frac{\text{A+}{{\text{ }\!\!\delta\!\!\text{ }}_{\text{m}}}}{\text{2}} \right)}{\text{sin}\left( \frac{\text{A}}{\text{2}} \right)}\] \[{{\delta }_{m}}=\] The correct order of stability is \[\text{ }\!\!\mu\!\!\text{ =cot}\left( \frac{\text{A}}{\text{2}} \right)\text{=}\frac{\text{cos}\left( \frac{\text{A}}{\text{2}} \right)}{\text{sin}\left( \frac{\text{A}}{\text{2}} \right)}\](c) \[\frac{\text{cos}\left( \frac{\text{A}}{\text{2}} \right)}{\text{sin}\left( \frac{\text{A}}{\text{2}} \right)}\text{=}\frac{\text{sin}\left( \frac{\text{A+}{{\text{ }\!\!\delta\!\!\text{ }}_{\text{m}}}}{\text{2}} \right)}{\text{sin}\left( \frac{\text{A}}{\text{2}} \right)}\]\[\Rightarrow \] value increases from \[\sin \left( \frac{\pi }{2}-\frac{A}{2} \right)=\sin \left( \frac{A}{2}+\frac{{{\delta }_{m}}}{2} \right)\] to \[\Rightarrow \] \[{{\delta }_{m}}=\pi -2A\]Oxidation state of Cr atom increases from + 1 to + 3.
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