A) \[\text{C}{{\text{u}}_{\text{4}}}\text{A}{{\text{g}}_{\text{2}}}\text{Au}\]
B) \[\text{C}{{\text{u}}_{\text{4}}}\text{A}{{\text{g}}_{4}}\text{Au}\]
C) \[\text{C}{{\text{u}}_{\text{4}}}\text{A}{{\text{g}}_{3}}\text{Au}\]
D) \[\text{CuAgAu}\]
Correct Answer: C
Solution :
Number of Cu atoms in the unit cell (fcc/ccp) \[=5\sqrt{3}\times {{10}^{-4}}=865\times {{10}^{-4}}wb\] Ag atoms occupying the edge centred \[{{\text{X}}_{\text{L}}}\text{=}{{\text{X}}_{\text{C}}}\] Au atoms presents at the body centred = 1 Hence, the formula is \[\text{ }\!\!\omega\!\!\text{ =}\frac{\text{1}}{\sqrt{\text{LC}}}\]
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