A) \[{{10}^{5}}:1\]
B) \[{{10}^{20}}:1\]
C) \[{{10}^{15}}:1\]
D) \[1:{{10}^{15}}\]
Correct Answer: C
Solution :
Radius of an atom \[={{r}_{A}}\approx {{10}^{-10}}m\] Radius of nucleus \[={{r}_{N}}\approx {{10}^{-15}}m\] So, ratio of their volumes is \[=\frac{6}{5}=1.2\Omega \] \[I=\frac{{{E}_{tot}}}{{{R}_{tot}}}=\frac{E+E}{{{r}_{1}}+{{r}_{2}}+R}\] \[=\frac{2E}{{{r}_{1}}+{{r}_{2}}+R}\] \[{{r}_{2}}\]
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