A) + 2 D
B) - 2 D
C) - 3 D
D) + 3 D
Correct Answer: D
Solution :
Given \[{{\varepsilon }_{r}}\] \[C=\frac{K{{\varepsilon }_{0}}A}{d}=15\mu F\] \[\frac{C}{{{C}_{0}}}=\frac{\frac{K{{\varepsilon }_{0}}A}{d}}{\frac{{{\varepsilon }_{0}}A}{d}}=\frac{15}{3}\] We know that \[\Rightarrow \] \[{{\varepsilon }_{r}}={{\varepsilon }_{0}}K\] \[=8.85\times {{10}^{-12}}\times 5\] \[=0.44\times {{10}^{-10}}\] \[\text{R= }\!\!\rho\!\!\text{ }\frac{\text{I}}{\text{a}}\] P = 3D
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