A) 90°-A
B) 2A
C) 180°-A
D) 180°-2A
Correct Answer: D
Solution :
The refractive index of a prism is given by \[=\frac{1}{2}C\times {{\left( 200 \right)}^{2}}\] ...(i) where, A = angle of prism \[\text{=2C }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{4}}}\text{J}\] angle of minimum deviation Given, \[\Delta \theta \] So, from Eq. (i). \[Q=ms\Delta \theta =0.1\times 250\times 0.4\] \[2C\times {{10}^{4}}=10\] \[\Rightarrow \] \[C=\frac{10}{2\times {{10}^{4}}}=5\times {{10}^{-4}}\] \[\therefore \] \[C=500\mu F\] \[{{C}_{0}}=\frac{{{\varepsilon }_{0}}A}{d}=3\mu F\]
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