A) \[\sqrt{2}W\]
B) \[\frac{1}{\sqrt{3}W}\]
C) \[\left( \sqrt{2}-1 \right)W\]
D) \[\frac{W}{\left( \sqrt{2}-1 \right)}\]
Correct Answer: D
Solution :
Work done by a magnet to turn from angle \[=\frac{1}{2}\frac{RT}{F}\] to \[\begin{align} & N{{H}_{4}}Cl\xrightarrow{\Delta }N{{H}_{3}}+HCl \\ & ABC \\ \end{align}\]is \[\begin{align} & N{{H}_{3}}+HCl\to N{{H}_{4}}Cl \\ & \text{Bwhite fumes} \\ \end{align}\] \[\begin{align} & N{{H}_{3}}+2{{K}_{2}}\left[ Hg{{I}_{4}} \right]+3KOH\to \\ & B\text{Nessler }\!\!'\!\!\text{ sreagent} \\ \end{align}\] \[\begin{align} & {{H}_{2}}NHgO.HgI+7KI+{{H}_{2}}O \\ & \text{brown ppt}\text{.} \\ & \text{iodineofMillion }\!\!'\!\!\text{ sbase} \\ \end{align}\] Also torque acting on the magnet is given by \[\begin{align} & HCl+MN{{O}_{3}}\to MCl+HN{{O}_{3}} \\ & \text{Cwhite ppt}\text{.} \\ \end{align}\] \[\left( M=A{{g}^{+}},p{{b}^{+}},H{{g}^{+}} \right)\] \[194u=\frac{28.9}{100}\times 194=56u\] \[\therefore \]
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