A) selecting a male is \[\frac{3}{2}\]
B) selecting a smoker is \[\frac{1}{5}\]
C) selecting anon - smoker is \[\frac{2}{5}\]
D) selecting a smoker, if a male is first selected, is given by \[\frac{8}{5}\]
Correct Answer: C
Solution :
Suppose, A:a man is selected B : a smoker is selected We are given that \[\begin{align} & N{{H}_{3}}+2{{K}_{2}}\left[ Hg{{I}_{4}} \right]+3KOH\to \\ & B\text{Nessler }\!\!'\!\!\text{ sreagent} \\ \end{align}\]The probability of selecting a smoker, \[\begin{align} & {{H}_{2}}NHgO.HgI+7KI+{{H}_{2}}O \\ & \text{brown ppt}\text{.} \\ & \text{iodineofMillion }\!\!'\!\!\text{ sbase} \\ \end{align}\] \[\begin{align} & HCl+MN{{O}_{3}}\to MCl+HN{{O}_{3}} \\ & \text{Cwhite ppt}\text{.} \\ \end{align}\] The probability of selecting a smoker, \[\left( M=A{{g}^{+}},p{{b}^{+}},H{{g}^{+}} \right)\] \[194u=\frac{28.9}{100}\times 194=56u\] \[\therefore \] The probability of selecting a male, \[\therefore \] \[56u=\frac{56}{14}Natom=4Natom\] \[\begin{align} & CaC{{O}_{3}}\xrightarrow{Heat}CaO+C{{O}_{2}}\uparrow \\ & \text{XColourless} \\ & \text{gas} \\ \end{align}\] Probability of selecting a smoler, if a male is first selected, is given by \[\begin{align} & CaO+{{H}_{2}}O\to Ca{{\left( OH \right)}_{2}} \\ & \text{ResidueY} \\ \end{align}\] \[\begin{align} & Ca{{\left( OH \right)}_{20}}+2C{{O}_{2}}\to Ca{{\left( HC{{O}_{3}} \right)}_{2}} \\ & \text{YExcessZ} \\ \end{align}\] \[\begin{align} & Ca{{\left( HC{{O}_{3}} \right)}_{2}}\xrightarrow{Heat}CaC{{O}_{3}}+C{{O}_{2}}\uparrow +{{H}_{2}}O \\ & ZX \\ \end{align}\]
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