A) 0
B) 2
C) 4
D) 7
Correct Answer: A
Solution :
Consider, \[\Delta \theta \] ...(1) \[Q=ms\Delta \theta =0.1\times 250\times 0.4\] \[2C\times {{10}^{4}}=10\] \[\Rightarrow \] \[C=\frac{10}{2\times {{10}^{4}}}=5\times {{10}^{-4}}\] ....(2) \[\therefore \] On adding Eqs. (i) and (ii), we get \[C=500\mu F\] \[{{C}_{0}}=\frac{{{\varepsilon }_{0}}A}{d}=3\mu F\] \[{{\varepsilon }_{r}}\] \[C=\frac{K{{\varepsilon }_{0}}A}{d}=15\mu F\] \[{{V}_{A}}:{{V}_{N}}={{10}^{15}}:1\] \[{{T}_{1/2}}=4.47\times {{10}^{8}}yr\] [ \[\frac{N}{{{N}_{0}}}=\frac{60}{100}={{\left( \frac{1}{2} \right)}^{n}}\] log 1 = 0] \[\Rightarrow \] \[{{2}^{n}}=\frac{10}{6}\]
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