A) k < 1
B) k > 2
C) k < 1 or k > 2
D) 1 < k < 2
Correct Answer: D
Solution :
Since, the points (1, 2, 3) and (2, -1, 0) lie on the opposite sides of the plane 2x + 3y ? 2z ? k = 0 \[\Omega \] \[\Omega \] (k ? 1) (k ? 2) < 0 ....(1) \[\Omega \] 1 < k < 2You need to login to perform this action.
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