A) \[\begin{align} & C{{H}_{3}}-CHOC{{H}_{2}}C{{H}_{2}}OH \\ & | \\ & C{{H}_{3}} \\ \end{align}\]
B) \[\begin{align} & C{{H}_{3}}-CHC{{H}_{2}}C{{H}_{2}}Br \\ & | \\ & C{{H}_{3}} \\ \end{align}\]
C) \[\begin{align} & C{{H}_{3}}-CH-C{{H}_{2}}C{{H}_{2}}OH \\ & | \\ & C{{H}_{3}} \\ \end{align}\]
D) \[\begin{align} & C{{H}_{3}}-CHOC{{H}_{2}}C{{H}_{3}} \\ & | \\ & C{{H}_{3}} \\ \end{align}\]
Correct Answer: C
Solution :
\[{{i}_{1}}=\frac{15}{1}mA=15mA\] \[R=250\Omega \]You need to login to perform this action.
You will be redirected in
3 sec