A) \[N{{a}^{+}}\]
B) \[M{{g}^{2+}}\]
C) \[A{{l}^{3+}}\]
D) \[{{\text{P}}^{\text{5+}}}\]
Correct Answer: D
Solution :
As the nuclear charge per electron is maximum in \[R=\frac{\Delta V}{\Delta l}=\frac{2.3-0.3}{10\times {{10}^{-3}}}\] Therefore, its size is smallest.
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