A) 5V
B) 10V
C) 0.2 V
D) 50 V
Correct Answer: B
Solution :
\[AB=\sqrt{{{\left( 2-0 \right)}^{2}}+{{\left( 3-4 \right)}^{2}}+{{\left( -1-1 \right)}^{2}}}\] \[=\sqrt{4+1+4}=3\] \[\text{l=}\frac{\text{100}}{\text{10}}\text{=10A}\] \[\text{E=}\frac{\text{1}}{\text{2}}\text{L}{{\text{l}}^{\text{2}}}\]You need to login to perform this action.
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