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VIT Engineering VIT Engineering Solved Paper-2014

  • question_answer
                   A circular current carrying coil has a radius R. The distance from the centre of the coil on the axis, where the magnetic induction will be \[\frac{1}{8}\]th to its value at the centre of the coil is

    A) \[\frac{R}{\sqrt{3}}\]                     

    B) \[R\sqrt{3}\]

    C) \[2\sqrt{3}R\]                   

    D) \[\frac{2}{\sqrt{3}}R\]

    Correct Answer: B

    Solution :

    \[\underset{ppt}{\mathop{\underset{Black}{\mathop{PbS}}\,}}\,+2C{{H}_{3}}COONa\] Also                   \[=5.6\times normality\]                   \[=5.6\times 1.5\]                    \[=8.4L\]                     \[MnO_{4}^{-}+4{{H}^{+}}+3{{e}^{-}}\to Mn{{O}_{2}}+2{{H}_{2}}O\]                  \[-{{E}_{3}}-\frac{-1.51\times 5+2\times 1.23}{3}\]                   \[\therefore \]


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