A) 4 sq units
B) 6 sq units
C) 1 sq units
D) 2 sq units
Correct Answer: D
Solution :
Since, |x| = 1 \[=5.6\times 1.5\] \[=8.4L\] \[MnO_{4}^{-}+4{{H}^{+}}+3{{e}^{-}}\to Mn{{O}_{2}}+2{{H}_{2}}O\] \[-{{E}_{3}}-\frac{-1.51\times 5+2\times 1.23}{3}\] \[\therefore \] Required area \[{{E}_{3}}=1.70V\] \[\left( V \right)={{a}^{3}}\] \[\therefore \] = 1+1 = 2 sq units
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