A) \[1\]
B) \[-1\]
C) \[{{2}^{n}}\]
D) \[{{2}^{n-1}}\]
Correct Answer: A
Solution :
For the sum of the coefficients in the expansion of \[{{(6a-5b)}^{n}},\]put \[a=b=1\] \[\therefore \]Sum of the coefficients \[={{(6-5)}^{n}}\] \[={{1}^{n}}=1\]
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