A) \[\frac{\lambda }{4{{\varepsilon }_{0}}}\]
B) \[\frac{\lambda }{8{{\varepsilon }_{0}}}\]
C) \[\frac{\lambda }{12{{\varepsilon }_{0}}}\]
D) \[\frac{\lambda }{16{{\varepsilon }_{0}}}\]
Correct Answer: C
Solution :
Length of the arc \[=r\theta =\frac{r\pi }{3}\] Charge on the arc \[=\frac{r\pi }{3}\times \lambda \] \[\therefore \] Potential at centre \[=\frac{kq}{r}\] \[=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{r\pi }{3}\frac{\lambda }{r}=\frac{\lambda }{12{{\varepsilon }_{0}}}\]You need to login to perform this action.
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