A) \[{{103}^{o}}\]
B) \[{{107}^{o}}\]
C) \[{{109}^{o}}28\]
D) \[\underline{X}\]
Correct Answer: C
Solution :
\[[\alpha ]=\frac{{{[\alpha ]}_{observed}}}{l\times C}=\frac{-1.2}{5\times \frac{6.15}{1000}}=-{{39}^{o}}\]
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