A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{4}\]
C) \[\pi \]
D) \[\frac{3\pi }{4}\]
Correct Answer: A
Solution :
\[\because \] \[{{\sin }^{-1}}x+{{\sin }^{-1}}y=\frac{\pi }{2}\] \[\therefore \] \[\frac{\pi }{2}-{{\cos }^{-1}}x+\frac{\pi }{2}-{{\cos }^{-1}}y=\frac{\pi }{2}\] \[\Rightarrow \] \[{{\cos }^{-1}}x+{{\cos }^{-1}}y=\frac{\pi }{2}.\]
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