A) \[NaI\]
B) \[NaBr\]
C) \[NaCl\]
D) \[NaN{{O}_{3}}\]
Correct Answer: A
Solution :
The liberated gas turns starch paper blue hence it must be iodine and substance X must contain an iodide. \[2NaI+2{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}N{{a}_{2}}S{{O}_{4}}+S{{O}_{2}}\] \[+{{I}_{2}}+2{{H}_{2}}O\] \[{{I}_{2}}+\]Starch\[\xrightarrow[{}]{{}}\]Starch-iodine complex (blue in colour)
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