A) Conversion of pyruvic acid to acetyl Co-A
B) Electron transport chain
C) Glycolysis
D) Krebs cycle
Correct Answer: B
Solution :
In glycolysis, four ATP and two \[NAD{{H}_{2}}\] molecules are formed. These two\[NAD{{H}_{2}}\]molecules go to electron transport chain. In oxidative decarboxylation, no ATP molecule is formed but two molecules of\[NAD{{H}_{2}}\]are formed from two molecules of pyruvate. These two\[NAD{{H}_{2}}\]go to electron transport chain. In Krebs cycle, two ATP, six\[NAD{{H}_{2}}\]and two molecules are formed from two molecules of acetyl Co-A. These \[NAD{{H}_{2}}\] and \[FAD{{H}_{2}}\]go to electron transport chain. In electron transport chain, all \[NAD{{H}_{2}}\]and \[FAD{{H}_{2}}\]pass to electron carriers and yield three ATP and two ATP molecules per \[NAD{{H}_{2}}\] and \[FAD{{H}_{2}}\] respectively. Thus, 4 ATP are formed in glycolysis 2 ATP in Krebs cycle and 34 ATP from electron transport chain 40 ATP Two ATP molecules are used during glycolysis. So, net gain of ATP molecules during one complete oxidation of a glucose molecule is 38 ATP.
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