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Uttarakhand PMT Uttarakhand PMT Solved Paper-2009

  • question_answer
    A hydrocarbon has carbon and hydrogen. Its molecular weight is 28. Its possible formula would be

    A)  \[{{C}_{3}}{{H}_{6}}\]         

    B)  \[{{C}_{2}}{{H}_{4}}\]

    C)  \[C{{H}_{4}}\]          

    D)  \[{{C}_{4}}{{H}_{8}}\]

    Correct Answer: B

    Solution :

     
    Compound Molecular weight
    \[{{C}_{3}}{{H}_{6}}\] \[12\times 3+6=42\]
    \[{{C}_{2}}{{H}_{4}}\] \[12\times 2+4=28\]
    \[C{{H}_{4}}\] \[12+4=16\]
    \[{{C}_{4}}{{H}_{8}}\] \[12\times 4+8=56\]
    Hence, the formula of the given compound is\[{{C}_{4}}{{H}_{4}}.\]


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