A) 32
B) 60
C) 18
D) 4
Correct Answer: B
Solution :
If all the elements having\[n>4\]are removed the number of elements that will be present in the periodic table are calculated as: \[n=1\]represents K shell and the number of elements having\[K\]shell \[=2\] \[[2{{n}^{2}}]\] \[n=2\]represents L shell and the number of elements having L shell\[=8\] \[n=3\]represents M shell and the number of elements having M shell =18 \[n=4\]represents N shell and the number of elements having N shell\[=32\] So the total number of elements having\[n<5\]are \[2+8+18+32=60\]
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