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Uttarakhand PMT Uttarakhand PMT Solved Paper-2008

  • question_answer
    Two pendulums have time periods T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

    A)  \[45{}^\circ \]           

    B)  \[90{}^\circ \]

    C)  \[60{}^\circ \]           

    D)  \[30{}^\circ \]

    Correct Answer: B

    Solution :

     When bigger pendulum of time period (5T/4) completes one vibration, the smaller pendulum will complete (5/4) vibrations. It means the smaller pendulum will be leading the bigger pendulum by phase T/4 second = \[\pi /2\]rad\[=90{}^\circ \]


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