A) zero
B) negative
C) positive
D) depend on molecular weight
Correct Answer: A
Solution :
Joule-Thomson effect is zero in an ideal gas in which van der Waals forces of attraction are negligible and there is no expenditure of energy in overcoming these force of attraction. Joule-Thomson coefficient\[({{\mu }_{JT}})\]is given by \[{{\mu }_{JT}}=-{\left[ \frac{H}{P} \right]}/{{{C}_{P}}}\;\] \[{{\mu }_{JT}}=0\]for ideal gas.
You need to login to perform this action.
You will be redirected in
3 sec
