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Uttarakhand PMT Uttarakhand PMT Solved Paper-2006

  • question_answer
    An ideal gas expands in volume from \[1\times {{10}^{-3}}{{m}^{3}}\]to\[1\times {{10}^{-2}}{{m}^{3}}\]at 300 K against a constant pressure of\[1\times {{10}^{5}}N{{m}^{-2}}\]. The work done is:

    A)  \[-900J\]         

    B)  \[-900kJ\]

    C)  \[270\text{ }kJ\]          

    D)  \[900\text{ }kJ\]

    Correct Answer: A

    Solution :

     Work done due to change volume against constant pressure: \[W=-P({{V}_{2}}-{{V}_{1}})\] \[=-1\times {{10}^{-5}}(1\times {{10}^{-2}}-1\times {{10}^{-3}})\] \[=-\text{ }900\text{ }Nm\] \[=-900J\]


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