A) \[32{{\pi }^{2}}T\]
B) \[24\pi {{R}^{2}}T\]
C) \[8\pi {{R}^{2}}T\]
D) \[4\pi {{R}^{2}}T\]
Correct Answer: A
Solution :
Initial surface energy \[{{\omega }_{1}}=2\times 4\pi {{R}^{2}}T=8\pi {{R}^{2}}T\] Final surface energy \[{{\omega }_{2}}=2\times 4\pi {{(2R)}^{2}}T=32\pi {{R}^{2}}T\]
You need to login to perform this action.
You will be redirected in
3 sec
