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SSC SSC CHSL TIER-I Solved Paper Held on 08.01.2017

  • question_answer
    If \[x+y=12\]and\[xy=32,\]then what is the value of \[({{x}^{2}}+{{y}^{2}})?\]

    A)  24

    B)  144

    C)  128

    D)  80

    Correct Answer: D

    Solution :

     \[x+y=12;\,xy=32\] \[\therefore \]\[{{x}^{2}}+{{y}^{2}}={{(x+y)}^{2}}-2xy\] \[={{(12)}^{2}}-2\times 32\] \[=144-64=80\]


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