A) Rs. 525
B) Rs. 1050
C) Rs. 260
D) Rs. 420
Correct Answer: A
Solution :
\[C.I.=P\left[ {{\left( 1+\frac{R}{100} \right)}^{T}}-1 \right]\] \[=12000\left[ {{\left( 1+\frac{10}{100} \right)}^{2}}-1 \right]\] \[=12000\left[ {{\left( \frac{11}{10} \right)}^{2}}-1 \right]\] \[=12000\left( \frac{121}{100}-1 \right)\] \[\therefore \]\[=\frac{1200\times 21}{100}=\text{Rs}\text{.}\,\text{252}\] \[\therefore \]\[\text{S}\text{.I}\text{.}=\frac{252}{2}=\text{Rs}\text{.}\,126\] \[\therefore \]\[\text{Principal=}\frac{\text{S}\text{.I}\text{. }\!\!\times\!\!\text{ 100}}{\text{Time }\!\!\times\!\!\text{ Rate}}\] \[\text{=}\frac{126\times 100}{3\times 8}\] \[=\text{Rs}\text{.}\,\text{525}\]
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