Answer:
Given: \[u=-30\text{ }cm,f=-15\text{ }cm.\]
We know that,
\[\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\]
\[\frac{1}{v}-\frac{1}{(-30)}=\frac{1}{(-15)}\]
\[\frac{1}{v}=\frac{-1}{15}-\frac{1}{30}\]
\[\frac{1}{v}=\frac{-2-1}{30}=\frac{-3}{30}=\frac{-1}{10}\]
\[v=-10\,cm\]
Characteristics of image:
(i) The image is formed at a distance of 10 cm from the concave lens on the left side.
(ii) Image formed is virtual.
(iii) Image formed is erect.
(iv) The size of the image formed is diminished.
You need to login to perform this action.
You will be redirected in
3 sec