Answer:
Given quadratic equation is, \[{{x}^{2}}-2kx-6=0\] \[x=3\] is a root of above equation, then \[{{(3)}^{2}}-2k(3)-6=0\] \[9-6k-6=0\] \[3-6k=0\] \[3=6k\] \[\therefore \] \[k=\frac{3}{6}=\frac{1}{2}\] \[k=\frac{1}{2}\]
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