Answer:
Given, height of cylinder \['h'=2.4\text{ }cm\] Radius of base \['r\text{ }\!\!'\!\!\text{ }=0.7\text{ }cm\] And slant height; \[l=\sqrt{{{h}^{2}}+{{r}^{2}}}\] \[=\sqrt{{{(2.4)}^{2}}+{{(0.7)}^{2}}}\] \[=\sqrt{6.25}\] \[=2.5\,\,cm\] Total surface area of the remaining solid = CSA of cylinder + CSA of cone + Area of top \[=2\pi rh+\pi rl+\pi {{r}^{2}}\] \[=\pi r[2h+l+r]\] \[=\frac{22}{7}\times 0.7[2\times 2.4+2.5+0.7]\] \[=2.2[4.8+2.5+0.7]\] \[=2.2\times 8=17.6\,\,c{{m}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec