Answer:
Ratio of sum of first n terms of two A.P.s are \[\frac{\frac{n}{2}\left[ 2a+(n-1)d \right]}{\frac{n}{2}\left[ 2A+(n-1)D \right]}=\frac{7n+1}{4n+27}\] Put \[n=17\] \[\Rightarrow \] \[\frac{2a+(16)d}{2A+(16)D}=\frac{120}{95}\] \[\frac{2a+(16)d}{2A+(16)D}=\frac{120}{95}=\frac{24}{19}\] \[\frac{a+8d}{A+8D}=\frac{24}{19}\] Hence ratio of 9th terms of two A.Rs is \[24:19\]
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