10th Class Mathematics Solved Paper - Mathematics 2017 Outside Delhi Set-I

  • question_answer
    In what ratio does the point \[\left( \frac{24}{11},y \right)\] divide the line segment joining the points \[P(2,-2)\] and \[Q(3,7)\]? Also find the value of y.

    Answer:

    Let point R divides PQ in the ratio \[k:1\]
                            \[R=\left( \frac{{{m}_{1}}{{x}_{2}}+{{m}_{2}}{{x}_{1}}}{{{m}_{1}}+{{m}_{2}}},\frac{{{m}_{1}}{{y}_{2}}+{{m}_{2}}{{y}_{1}}}{{{m}_{1}}+{{m}_{2}}} \right)\]
    \[\Rightarrow \]    \[\left( \frac{24}{11},y \right)=\left( \frac{k(3)+1(2)}{k+1},\frac{k(7)+1(-2)}{k+1} \right)\]
                              \[=\left( \frac{3k+2}{k+1},\frac{7k-2}{k+1} \right)\]
    \[\Rightarrow \]            \[\frac{3k+2}{k+1}=\frac{24}{11}\]
    \[\Rightarrow \]        \[11(3k+2)=24(k+1)\]
    \[\Rightarrow \]         \[33k+22=24k+24\]
    \[\Rightarrow \]       \[33k-24k=24-22\]
    \[\Rightarrow \]                 \[9k=2\Rightarrow k=2/9\]
    \[\therefore \]                   \[k:1=2:9\]
    Now,                 \[y=\frac{7k-2}{k+1}=\frac{7\left( \frac{2}{9} \right)-2}{\frac{2}{9}+1}\]
                               \[=\frac{\frac{14}{9}-2}{\frac{2}{9}+1}=\frac{\frac{14-18}{9}}{\frac{2+9}{9}}=\frac{-4}{11}\]
    Line PQ divides in the ratio \[2:9\] and value of \[y=\frac{-4}{11}\]


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