Answer:
We have, \[\sqrt{3}{{x}^{2}}-2\sqrt{2}x-2\sqrt{3}=0\] \[\Rightarrow \sqrt{3}{{x}^{2}}-3\sqrt{2}x+\sqrt{2x}-2\sqrt{3}=0\] \[\Rightarrow \sqrt{3}x(x-\sqrt{6})+\sqrt{2}(x-\sqrt{6})=0\] \[\Rightarrow (\sqrt{3}x+\sqrt{2})(x-\sqrt{6})=0\] \[\Rightarrow x=-\sqrt{\frac{2}{3}}\] or \[\sqrt{6}\]
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