question_answer

In a rectangle ABCD, E is middle point of AD. If \[AD=40\text{ }m\] and \[AB=48\text{ }m\], then find EB.

Answer:

Given, E is the mid-point of AD

\[\therefore AE=\frac{40}{2}=20\,m\]

\[\angle A=90{}^\circ \]             [Angle of a rectangle]

\[\therefore \,\text{In}\,\,\text{rt}.\,\,\Delta \,BAE,\]

\[E{{B}^{2}}=A{{B}^{2}}+A{{E}^{2}}\]   [Pythagoras? theorem]

\[={{(48)}^{2}}+{{(20)}^{2}}\]

\[=2304+400=2704\]

\[EB=\sqrt{2704}=52\,\,m\]