Railways R.R.C. (Patna) Solved Paper Held on 2nd Shift 9-11-2014

  • question_answer
    A man spends\[\frac{1}{3}rd\] of the money with him on clothes, \[\frac{1}{5}\]the of the remaining on food and \[\frac{1}{4}\]th of remaining on travel. Now, he is left with Rs. 120. How much money the man had in the beginning?

    A) Rs. 250

    B)               Rs. 200

    C) Rs. 300 

    D) Rs. 450

    Correct Answer: C

    Solution :

    Let, the man had Rs x in the beginning then, \[x\times \frac{1}{3}+\left( x-\frac{x}{3} \right)\times \frac{1}{5}+\left( x-\frac{x}{3}-\frac{2x}{15} \right)\times \frac{1}{4}+120=x\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{x}{3}+\frac{2x}{15}+\frac{8x}{60}+120=x\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\frac{20x+8x+8x+7200}{60}=x\] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{36x+7200=60x}{{}}\]                             \[x=\frac{7200}{24}\]                                \[=Rs.300\]


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