A) 48
B) 96
C) 102
D) 55
Correct Answer: B
Solution :
Other digonal \[=2\sqrt{{{(10)}^{2}}-{{\left( \frac{12}{2} \right)}^{2}}}\] \[=2\sqrt{100-36}\] \[=2\sqrt{64}\] \[=2\times 8=16\,\,cm\] Now, the area of a rhombus \[=\frac{1}{2}\times 12\times 16\] \[=96\,\,sq.\,cm\]
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