Railways R.R.C. (Hazipur) Solved Paper Held on 1-12-2013

  • question_answer
    \[\frac{b}{a}=0.25,\]then \[\frac{2a-b}{2a+b}+\frac{2}{9}=?\]

    A) \[\frac{4}{9}\]                          

    B) \[\frac{5}{9}\]

    C) 1         

    D) 2

    Correct Answer: C

    Solution :

    If \[\frac{b}{a}\]= 0-25 then, \[\frac{2a-b}{2a+b}+\frac{2}{9}=\frac{2-\frac{b}{a}}{2+\frac{b}{a}}+\frac{2}{9}\] \[=\frac{2-0.25}{2+0.25}+\frac{2}{9}\] \[=\frac{7}{9}+\frac{2}{9}\] \[=\frac{9}{9}\] \[=1\]                        


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