• question_answer Father is aged three times more than his son Rohit. After 8 years, he would be two and half times of Rohit's age. After further 8 years, how many times would he be of Rohit's age? A) 2 times             B) $2\,\,\frac{1}{2}$timesC) $2\,\,\frac{3}{4}$times             D) $2\frac{1}{5}$times

Let Rohit's age = x years His father's age $=3x$year After 8 years Rohit's age = (x+8) years Father' sage = (3x+8) years As per question, $3x+8=\frac{5}{2}(x+8)$ $\Rightarrow 6x+16=5x+40$ $x=24\,\,years$ After further 8 years Rohit's age = x +8+8 = 24+8+8 = 40 years Father's age = $3x$+8+8 $=3\times 24+8+8$ $=3\times 24+8+8$ =88 years           $\therefore \frac{Father's\,\,age}{Son's\,\,age}=\frac{88}{40}$ $=2\frac{1}{5}$