Railways R.R.C. (Delhi) Solved Paper Held on 1st Shift 23-11-2014

  • question_answer Father is aged three times more than his son Rohit. After 8 years, he would be two and half times of Rohit's age. After further 8 years, how many times would he be of Rohit's age?

    A) 2 times             

    B) \[2\,\,\frac{1}{2}\]times

    C) \[2\,\,\frac{3}{4}\]times             

    D) \[2\frac{1}{5}\]times

    Correct Answer: D

    Solution :

    Let Rohit's age = x years His father's age \[=3x\]year After 8 years Rohit's age = (x+8) years Father' sage = (3x+8) years As per question, \[3x+8=\frac{5}{2}(x+8)\] \[\Rightarrow 6x+16=5x+40\] \[x=24\,\,years\] After further 8 years Rohit's age = x +8+8 = 24+8+8 = 40 years Father's age = \[3x\]+8+8 \[=3\times 24+8+8\] \[=3\times 24+8+8\] =88 years           \[\therefore \frac{Father's\,\,age}{Son's\,\,age}=\frac{88}{40}\] \[=2\frac{1}{5}\]

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